2^x2-12x+32=x2

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Solution for 2^x2-12x+32=x2 equation: 



2^x2-12x+32=x2

We move all terms to the left:

2^x2-12x+32-(x2)=0

We add all the numbers together, and all the variables

-1x^2-12x+2^x2+32=0

We move all terms containing x to the left, all other terms to the right

-1x^2-12x+2^x2=-32

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